Sum square difference

The sum of the squares of the first ten natural numbers is, $$1^2 + 2^2 + ... + 10^2 = 385$$ The square of the sum of the first ten natural numbers is, $$(1 + 2 + ... + 10)^2 = 55^2 = 3025$$ Hence the difference between the sum of the squares of the first ten natural numbers and the square of the sum is $3025 - 385 = 2640$. Find the difference between the sum of the squares of the first one hundred natural numbers and the square of the sum.

Comment used to generate the code:

function that finds the difference between the sum of the squares of the first n natural numbers and the square of the sum of the first n natural numbers

function sumSquareDifference(n: number): number {

      let sumOfSquares = 0;

      let squareOfSums = 0;

      for (let i = 1; i <= n; i++) {

          sumOfSquares += Math.pow(i, 2);

          squareOfSums += i;

      }

      squareOfSums = Math.pow(squareOfSums, 2);

      return squareOfSums - sumOfSquares;

    }

Thoughts:

Another fun little mathematical problem being solved by crawling up the list of numbers, I wonder if there's a way to do this in a more efficient way.